Let's start with a warm-up ratio problem. We have the ratio 13/6 = 5/X. To eliminate X in the denominator, we can multiply both sides of the equation by X. This cancels out the X on the right-hand side, resulting in 13/6X = 5. To solve for X, we can multiply both sides by the inverse of 13/6, which is 6/13. This cancels out the 13/6 on the left-hand side, leaving us with X = 5 * 6/13, which simplifies to 30/13. Another way to solve this problem is through cross multiplication. We start with 13/6 = 5/X. By cross multiplying, we get 13X = 5 * 6. Dividing both sides by 13 gives us X = 30/13. Now, let's move on to some word problems. The highest mountain in Canada, Mount Yukon, has a size of 298/67 compared to the size of Ben Nevis. We can represent the size of Yukon as 298/67 = N/1, where N represents the size of Ben Nevis. Next, we have information about Mount Elbert in Colorado, the highest peak in the Rocky Mountains. Mount Elbert's size is 220/67 compared to Ben Nevis. We can represent the size of Elbert as E = 220/67 * N. Additionally, we are given information about Mount Blanc, with a size of 44/48 compared to Ben Nevis. Representing the size of Blanc as B = 44/48, we know that Mount Blanc is 4,800 meters high. To determine the height of Mount Yukon, we need to work backwards and find the values for all the variables in between. Using the given information, we have B = 4,800 meters and E = 44/48 * B. Dividing 4,800 by 48 gives us the value for E: E = 44 * 100 = 4,400 meters. Substituting the value of E into the equation for E, we get 4,400...